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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

For a particle moving along a circular path, the radial acceleration $a_{r}$ is proportional to time $t$ . If $a_{t}$ is the tangential acceleration, then which of the following will be independent of time $t$ ?

Options:

Answer:

Solution:

$a_{r} \propto t; \frac{v^{2}}{r} = kt$

$v^{2} = krt; 2 v \frac{d v}{d t} = kr$

$a_{t} = \frac{kr}{2 v} = \frac{kr}{2 \sqrt{rkt}} = \frac{1}{2} \sqrt{\frac{kr}{t}}$

$a_{t}^{2} a_{r} = \frac{1}{4} \frac{kr}{t} \times kt = independent of t$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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