A stone of mass 1 kg is tied to end of a massless string of length 1 m . If the breaking tension of the string is 400 N , then maximum linear velocity, the stone can have without breaking the string,

Question

A stone of mass 1 kg is tied to end of a massless string of length 1 m . If the breaking tension of the string is 400 N , then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is:

TestHub · Accepted Answer

In horizontal circle, tension towards the centre of the circular path at any moment will provide the required centripetal force. Therefore, T m a x = m v 2 r ⇒ 400 = 1 × v 2 1 ⇒ v = 20 m s - 1

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