If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
(Take : $g = 10 {ms}^{- 2}$ , the radius of earth, $R = 6400 \times 10^{3} m$ , Take $π = 3.14$ )

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For objects to float, m g = m ω 2 R ω = angular velocity of the earth. R = Radius of earth ω = g R . . . 1 Duration of day = T T = 2 π ω . . . 2 ⇒ T = 2 π R g = 2 π 6400 × 10 3 10 ⇒ T 60 = 83 . 775 minutes ≃ 84 minutes

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