Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsMedium2 minQB

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A man M slides down a curved frictionless track, starting from rest. The curve obeys the equation $y = \frac{x ^{2}}{2}$ . The tangential acceleration of man is :

Options:

Answer:

Solution:

$a_{t} = g \frac{\frac{d y}{d x}}{1 + ( \frac{d y}{d x} ) ^{2}}$

$y = \frac{x ^{2}}{2} \Rightarrow \frac{d y}{d x} = x$

$a_{t} = g \frac{x}{1 + x ^{2}}$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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