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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Particles are released from rest at $A$ and slide down the smooth surface of height $h$ to a conveyor $B$ . The correct angular velocity $ω$ of the conveyor pulley of radius $r$ to prevent any sliding on the belt as the particles transfer to the conveyor is

Options:

Answer:

Solution:

First of all, we have to calculate the velocity of particles at the point B.

$∵$ Loss in P.E. = gain in K.E.

Or $m g h = \frac{1}{2} m v^{2}$

$∴$ $v = \sqrt{2 g h}$

To prevent sliding, $v = r ω$

$∴$ $ω = \frac{v}{r} = \frac{\sqrt{2 g h}}{r}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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