In one second a particle moves with constant speed from point A to point B along the circular track of radius 1.0 m as shown in the figure. The average acceleration $($ in $m / s^{2})$ of the particle during this motion.

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TestHub · Accepted Answer

v = T im e D i s t an ce ​ = Δ t π R ​ = 1 π ( 1 ) ​ = πm / s v i ​ = π i ^ v f ​ = − π i ^ a a vg ​ = Δ t v f ​ − v i ​ ​ a a vg ​ = 1 − π i ^ − π i ^ ​ a a vg ​ = − 2 π i ^ m / s 2 ∣ a a vg ​ ∣ = 2 πm / s 2 ≈ 6.28 m / s 2

Physics - Circular Motion Question with Solution | TestHub

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