Physics - Circular Motion Question with Solution | TestHub

For body to move on circular path. Frictional force provides the necessary centripetal force,

$ie,$frictional force = centripetal force

$\mathrm{o}\mathrm{r}\mathrm{ } \mu mg=\frac{{mv}_0^2}{r}={mr\omega }^2$

$\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{ }\mathrm{\mu }g={r\omega }^2$

$\therefore 0.5\times 9.8={10 \omega }^2$

$\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{ }\mathrm{\omega }=0.7\mathrm{ }{\mathrm{r}\mathrm{a}\mathrm{d}\mathrm{ }\mathrm{s}}^{-1}$