Physics - Circular Motion Question with Solution | TestHub

$v=900{\text{km h}}^{-1}$

$=\text{900}\times \frac{5}{\text{18}}$

$=\text{250}{m\; s}^{-1}$



maximum force is at the bottom of vertical circle

${\text{F}}_{\text{max}}=\frac{{\text{mv}}^2}{\text{r}}+\text{mg}=5mg$

${\text{v}}^2=\text{4gr}$

$\text{r}=\frac{{\text{v}}^2}{\text{4g}}=\frac{{\left(\text{250}\right)}^2}{4\left(\text{9.8}\right)}=\text{1594}m$