A steel wire can withstand a load up to 2940 N . A load of 150 kg is suspended from a rigid support. The maximum angle through which the wire can be displaced from the mean position, so that the wire

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A steel wire can withstand a load up to 2940 N . A load of 150 kg is suspended from a rigid support. The maximum angle through which the wire can be displaced from the mean position, so that the wire does not break when the load passes through the position of equilibrium, is

TestHub · Accepted Answer

While crossing the equilibrium position

$T = m g + \frac{m v^{2}}{r} = m g + \frac{m}{l} [2 g l (1 - \cos θ)]$

$= m g + 2 m g - 2 m g \cos θ = μ γ [3 - 2 \cos θ]$

$∴ 3 - 2 \cos θ = \frac{2940}{(150) (9.8)} = 2$

$\Rightarrow 2 \cos θ = 1 \Rightarrow \cos θ = \frac{1}{2} \Rightarrow θ = 60 °$

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