Physics - Circular Motion Question with Solution | TestHub

When driver applies brakes and the car covers distance $x$ before coming to rest, under the effect of retarding force $F$. Then $$\begin{array}{rl}\frac{1}{2}m{v}^2& =Fx\\ x& =\frac{m{v}^2}{2F}\end{array}$$ or But when he takes turn, then $$\begin{array}{rl}\frac{m{v}^2}{r}& =F\\ r& =\frac{m{v}^2}{F}\end{array}$$ It is clear that $x=\frac{r}{2}$ ie, by the same retarding force the car can be stopped in a less distance if the driver apply brakes. This retarding force is actually a friction force.