A disc rotates about its axis of symmetry in a horizontal plane at a steady rate of 3.5 revolutions per second. A coin placed at a distance of 1 .25 cm from the axis of rotation remains at rest on the

Question

A disc rotates about its axis of symmetry in a horizontal plane at a steady rate of 3.5 revolutions per second. A coin placed at a distance of 1 .25 cm from the axis of rotation remains at rest on the disc. The coeﬃcient of friction between the coin and the disc is g = 10 m s - 2

TestHub · Accepted Answer

3 .5 rev s - 1 1 r e v → 2 π rad 3 .5 rev → 2 π × 3 .5 rad ⇒ ω = 7 π rad s - 1 μ m g = m v 2 1.25 μ m g = m r ω 2 r μ m g = m r ω 2 μ = r ω 2 g = 1.25 × 10 - 2 × 7 × 22 7 2 10 = 1.25 × 10 - 2 × 22 2 10 = 0.6

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