The angular displacement of body performing circular motion is given by θ = 5 sin 6 π t . The angular velocity of the body at t = 3 second will be [ sin 2 π = 1 , cos 2 π = 0 ]

θ = 5 sin 6 π t ∴ dt d θ = 6 π ⋅ 5 cos 6 π t At t = 3 s , dt d θ = 6 5 π cos 6 π × 3 = 6 5 π cos 2 π = 0

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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2021

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The angular displacement of body performing circular motion is given by $θ = 5 sin \frac{π t}{6}$ . The angular velocity of the body at $t = 3$ second will be $[sin \frac{π}{2} = 1, cos \frac{π}{2} = 0]$

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$θ = 5 sin \frac{π t}{6} ∴ \frac{d θ}{dt} = \frac{π}{6} \cdot 5 cos \frac{π t}{6} At t = 3 s, \frac{d θ}{dt} = \frac{5 π}{6} cos \frac{π \times 3}{6} = \frac{5 π}{6} cos \frac{π}{2} = 0$

Stream:MHT_CETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2021

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