Physics - Center of Mass Question with Solution | TestHub

From the graph, it is a straight line so, uniform motion. Because of impulse direction of velocity changes as can be seen from the slope of the graph. $$\begin{array}{rl}& \text{ Initial velocity }=\frac{2}{2}=1\mathrm{m}/\mathrm{s}\\ & \text{ Final velocity }=-\frac{2}{2}=-1\mathrm{m}/\mathrm{s}\\ & {\bar{P}}_{\mathrm{i}}=0.4\mathrm{N}-\mathrm{s}\\ & {\overline{\mathrm{P}}}_{\mathrm{i}}=-0.4\mathrm{N}-\mathrm{s}\\ & \overrightarrow{\mathrm{J}}={\overline{\mathrm{P}}}_{\mathrm{i}}-{\overline{\mathrm{P}}}_{\mathrm{i}}=-0.4-0.4=-0.8\mathrm{N}-\mathrm{s}(\overrightarrow{\mathrm{J}}=\text{ impulse })\\ & |\overrightarrow{\mathrm{J}}|=0.8\mathrm{N}-\mathrm{s}\end{array}$$