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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium2 min

PhysicsMediumsingle choice

Block A of mass 1 kg is hanging at rest from a vertical spring of spring constant $k = 600 N / m$ . Block B of 1 kg mass strikes the block A with velocity v and sticks to it. Then the value of v for which the spring just attains natural length is

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Solution:

$2 mg (x_{0}) = \frac{1}{2} kx_{0}^{2} + \frac{1}{2} 2 m (\frac{v}{2})^{2}$ and $x_{0} = \frac{mg}{k} \Rightarrow v = g \frac{6 m}{k} = 1 m / s$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

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