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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minQB

PhysicsMediumsingle choice

A body of mass $m_{1}$ strikes a stationary body of mass $m_{2}$ . If the collision is elastic and head-on, the fraction of kinetic energy transmitted by the first body to the second body is :

Options:

Answer:

Solution:

$v_{2} = \frac{2 m _{1}}{m _{1} + m _{2}} v \Rightarrow \frac{K _{2}}{K _{1}} = \frac{\frac{1}{2} m _{2} v _{2}^{2}}{\frac{1}{2} m _{1} v ^{2}} = \frac{4 m _{1} m _{2}}{( m _{1} + m _{2} ) ^{2}}$

Ans. (C)

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: QB

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