Physics - Center of Mass Question with Solution | TestHub
A body of mass m1 collides one-dimensionally with another stationary body of mass m2. The coefficient of restitution is e. Match each condition in Column-I with the correct option(s) of Column-II.
Column I | Column II |
|---|---|
(A) After the collision, velocity of the second body is maximum when | (P) e = 1 |
(B) After the collision, momentum of the second body is maximum when | (Q) m1 >> m2 |
(C) After the collision, kinetic energy of the second body is maximum when | (R) e = 0 |
(D) After the collision, kinetic energy of the system is minimum when | (S) m1 << m2 |
| (T) m2 = m1 |
Options:
Answer:
Solution:
With :
(A) v2 maximum: e = 1 and m1 >> m2 -> P,Q. (B) p2 = m2v2 (for fixed m1) grows with m2: e = 1 and m1 << m2 -> P,S. (C) KE of m2 = p2²/2m2, maximised at m1 = m2 with e = 1 -> P,T. (D) system KE minimum = maximum loss: e = 0 -> R. Ans. A-P,Q; B-P,S; C-P,T; D-R
