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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassImpulse momentum theoremMedium2 minQB

PhysicsMediuminteger

A rubber ball of mass 0.5 kg strikes a rigid wall perpendicularly with a speed of 10 m/s and rebounds with a speed of 8 m/s. The magnitude of the impulse exerted by the wall on the ball in Ns is:

Answer:

Solution:

Given: $m = 0.5$ kg, initial velocity $v_{i} = + 10$ m/s (towards the wall), rebound velocity $v_{f} = - 8$ m/s (opposite direction).

Impulse = change in momentum:

$J = Δ p = m (v_{f} - v_{i})$

$J = 0.5 (- 8 - 10) = 0.5 \times (- 18) = - 9$ Ns

Magnitude: $∣ J ∣ = 9$ Ns

Answer: 9

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem

⏱ 2mℹ️ Source: QB

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