Physics - Center of Mass Question with Solution | TestHub
PhysicsCenter of MassImpulse momentum theoremHard2 minQB
PhysicsHardnumerical range
Three particles A, B and C of mass m, 2m and 3m respectively lie on a smooth horizontal table. A and B as well as B and C are connected by light inextensible strings each of equal length . The string connecting A and B is tight. The initial distance between B and C is and particle C is given a velocity v0 parallel to AB as shown in the figure. Find the velocity of the particle A, just after its starts moving. ( )
Answer:
0.10
Solution:
BC becomes taut when : C has moved parallel to AB, so BC makes 60° with AB.
Impulse along BC and along AB. Inextensibility: A's speed along AB = B's component along AB ⇒ ; C's component along BC = B's along BC ⇒ .
, so m/s
Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem
⏱ 2mℹ️ Source: QB
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