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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

PhysicsMediumsingle choice

A body is released from a height equal to the radius $(R)$ of the earth. The velocity of the body when it strikes the surface of the earth will be: (Given $g =$ acceleration due to gravity on the earth.)

Options:

Answer:

Solution:

Using conservation of mechanical energy,
$U_{i} + K_{i} = U_{f} + K_{f}$
$\Rightarrow - \frac{G M m}{2 R} + 0 = - \frac{G M m}{R} + \frac{1}{2} m v^{2}$
$\Rightarrow \frac{1}{2} m v^{2} = \frac{G M m}{2 R}$
$\Rightarrow v = \sqrt{\frac{GM}{R}} = \sqrt{g R}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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