Physics - Center of Mass Question with Solution | TestHub

The coordinates of C.M of three particle are $\mathrm{x}$=$\frac{{\mathrm{m}}_1{\mathrm{x}}_1+{\mathrm{m}}_2{\mathrm{x}}_2+{\mathrm{m}}_3{\mathrm{x}}_3}{{\mathrm{m}}_1+{\mathrm{m}}_2+{\mathrm{m}}_3}$ and $\mathrm{y}$=$\frac{{\mathrm{m}}_1{\mathrm{y}}_1+{\mathrm{m}}_2{\mathrm{y}}_2+{\mathrm{m}}_3{\mathrm{y}}_3}{{\mathrm{m}}_1+{\mathrm{m}}_2+{\mathrm{m}}_3}$ $\text{ here }$$m_1=m_2=m_3=m$ $\text{ so }$$\mathrm{x}$=$\frac{\left({\mathrm{x}}_1+{\mathrm{x}}_2+{\mathrm{x}}_3\right)\mathrm{m}}{\mathrm{m}+\mathrm{m}+\mathrm{m}}$=2$$x=\frac{\left(x_1+x_2+x_3\right)m}{m+m+m}=2,y=\frac{\left(y_1+y_2+y_3\right)m}{m+m+m}=2$$ so coordinates of $\mathrm{C}.\mathrm{M}$. of three particle are (2,2)