A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at

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A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

TestHub · Accepted Answer

​ τ Net ​ = 0 ⇒ ( 400 g × 30 ) = ( 250 g × 10 ) ( mg × 50 ) m = 50 12000 − 2500 ​ = 50 9500 ​ M = 190 g ​

Physics - Center of Mass Question with Solution | TestHub

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