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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationEasy2 minai-gemini

PhysicsEasysingle choice

A system consists of two blocks of masses $m_{1}$ and $m_{2}$ connected by a light spring on a smooth horizontal surface. Initially, the spring is compressed, and the system is held at rest. When the system is released, the blocks move apart. If the speed of the block $m_{1}$ is $v_{1}$ at a certain instant, what is the speed of the block $m_{2}$ at that same instant?

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Solution:

The system of two blocks and the spring is isolated, meaning there are no external forces acting on it in the horizontal direction. Therefore, the total momentum of the system must be conserved.

$m_{1} v_{1} = m_{2} v_{2}$ $v_{2} = \frac{m _{1}}{m _{2}} v_{1}$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 2mℹ️ Source: ai-gemini

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Physics - Center of Mass Question with Solution | TestHub

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