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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minQB

PhysicsMediummultiple choice

A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions along x and y axis.

Options:(select one or more)

Answer:

A, B, C

Solution:

Momentum conservation: $m v \hat{i} + m v \hat{j} + 2 m v^{'} = 0 \Rightarrow v^{'} = - \frac{v}{2} (\hat{i} + \hat{j}), ∣ v^{'} ∣ = \frac{v}{2}$

Each component of the 2m fragment's momentum has magnitude mv (A, B correct).

Energy released: $\frac{1}{2} m v^{2} + \frac{1}{2} m v^{2} + \frac{1}{2} (2 m) \frac{v ^{2}}{2} = \frac{3}{2} m v^{2}$ (C correct, D wrong).

Subject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: QB

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