Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisEasy2 minQB

PhysicsEasynumerical

In the given figure, the charge stored in $6 μ F$ capacitor, when points $A$ and $B$ are joined by a connecting wire is _______ $μ C$ .

Answer:

36.00

Solution:

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram.

$R_{e q} = 9Ω$

$i = \frac{9 V}{9Ω} = 1 A$

$Δ V_{6Ω} = 1 \times 6 = 6 V$

$V_{A} = 3 V$

So, potential difference across $6 μ F$ is $6 V .$

Hence, $Q = C Δ V$

$= 6 \times 6 \times 1 0^{- 6} C$

$= 36 μ C$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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