The figure shows two thin large identical parallel conducting plates placed in air (dielectric constant = 1 ) with a slab of dielectric constant k placed between them. The width of the small gap betwe

Question

The figure shows two thin large identical parallel conducting plates placed in air (dielectric constant $= 1$ ) with a slab of dielectric constant k placed between them. The width of the small gap between the conducting plates is d while the thickness of the dielectric slab is $t$ . The conducting plates are given equal and opposite charges due to which the strength of the electric field in air region is E as shown. The area of plates perpendicular to the plane of figure is A and consider it to be large. Neglect the edge effects. (The portion ABCD has the same dimensions perpendicular to the plane of the figure as that of plate or dielectric medium). Mark the INCORRECT option(s) :

TestHub · Accepted Answer

Applying Gauss theorem to volume containing cuboid indicated by ABCD $- \frac{E}{K} A + \frac{0}{A} = \frac{q _{enc}}{ϵ _{0}}$ or $q_{enc} = - \frac{EA ϵ _{0}}{K}$

Electrostatic energy stored in dielectric medium $= \frac{1}{2} k \in_{0} (\frac{E}{K})^{2} A t = \frac{\in _{0} E ^{2} A t}{2 K}$

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Options:(select one or more)

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JEE Advanced (2028)