The total charge on the system of capacitance $C_{1} = 1 μF, C_{2} = 2 μF, C_{3} = 4 μF$ and $C_{4} = 3 μF$ connected in parallel is
(Assume a battery of $20 V$ is connected to the combination)

Question

The total charge on the system of capacitance C 1 = 1 μF , C 2 = 2 μF , C 3 = 4 μF and C 4 = 3 μF connected in parallel is (Assume a battery of 20 V is connected to the combination)

TestHub · Accepted Answer

As the given capacitors are in parallel combination, therefore, C eq = 1 + 2 + 3 + 4 μF = 10 μF Hence, charge flown through the switch ∴ Q = 20 V × 10 μF = 200 μ C

Physics - Capacitor Question with Solution | TestHub

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