Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCapacitanceMedium2 minQB

PhysicsMediummultiple choice

A parallel-plate capacitor is connected to a cell. Its positive plate A and its negative plate B have charges +Q and -Q respectively. A third plate C , identical to A and B , with charge +Q , is now introduced midway between A and B , parallel to them. Which of the following are correct?

Options:(select one or more)

Answer:

A, B, C, D

Solution:

Initially $\Rightarrow C = \frac{ϵ _{0} A}{d}$

$V = \frac{Q}{C}$

$= \frac{Qd}{ϵ _{0} A}$

Finally

$C_{1} = C_{2} = \frac{2 ϵ _{0} A}{A}$

$V_{1} = \frac{Q d}{2.2 ϵ _{0} A}$

$V_{2} = \frac{3 Q d}{2.2 ϵ _{0} A}$

$V = V_{1} + V_{2} = \frac{d}{ϵ _{0} A}$

$V_{f} = V_{i}$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Capacitance

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...