A combination of parallel plate capacitors is maintained at a certain potential difference.

When a $3 mm$ thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by $2.4 mm$ . Find the dielectric constant of the slab.

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TestHub · Accepted Answer

Assume initial separation as 3 mm each capacitance C 1 = ε 0 A 3 before C 1 = k ε 0 A 3 . ε 0 A 2.4 k ε 0 A 3 + ε 0 A 2.4 to get same capacitance ε 0 A 3 = k ε 0 A 3 . ε 0 A 2.4 k ε 0 A 3 + ε 0 A 2.4 3 k = 2.4 k + 3 0.6 k = 3 ⇒ k = 3 0.6 k = 30 6 = 5 .

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