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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisEasy2 minQB

PhysicsEasysingle choice

A parallel plate capacitor of capacitance $1 μ F$ is charged to a potential difference of 20 V . The distance between plates is $1 μ m$ . The energy density between plates of capacitor is.

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Answer:

Solution:

$Energy density = \frac{1}{2} ε_{0} E^{2} = \frac{1}{2} ε_{0} (\frac{V}{d})^{2} = \frac{1}{2} (8.85 \times 1 0^{- 12}) (\frac{20}{1 0 ^{- 6}})^{2} J / m^{3} ≃ 1.8 \times 1 0^{3} J / m^{3}$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: QB

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