In the given circuit, a charge of + 80 μ C is given to the upper plate of the 4 μ F capacitor. Then in the steady state, the charge on the upper plate of the 3 μ F capacitor is

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The total charge on plate A will be 80 μ C . 2 μ F and 3 μ F capacitors are in parallel. Therefore, C e q ​ = 2 + 3 = 5 HF Charge on capacitor of 3 μ F capacitance q = 5 3 ​ × 80 = 48 μ C

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