Physics - Capacitor Question with Solution | TestHub

As required equivalent capacitance should be $C_{\mathrm{eq}}=\frac{6}{13}\mu \mathrm{F}$ Therefore three capacitors must be in parallel and 4 must be in series with it. $\frac{1}{{\mathrm{C}}_{\mathrm{eq}}}=\left[\frac{1}{3\mathrm{C}}\right]+\left[\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}\right]$ $C_{\mathrm{eq}}=\frac{3\mathrm{C}}{13}=\frac{6}{13}\mu \mathrm{F}[$ as $\mathrm{C}=2\mu \mathrm{F}]$ So, desired combination will be as below: