Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence ca

Question

Two capacitors, each having capacitance 40 μ F are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 μ F . The value of K will be :

TestHub · Accepted Answer

When a dielectric is inserted between the sheets of a capacitor, its capacitance becomes $K C$ .
Now the equivalent capacitance in series combination will be,
$C_{eq} = \frac{C \times K C}{C (1 + K)} \Rightarrow 24 = \frac{40 K}{1 + K} \Rightarrow K = 1.5$

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