A capacitor has air as dielectric medium and two conducting plates of area 12 cm 2 and they are 0.6 cm apart. When a slab of dielectric having area 12 cm 2 and 0.6 cm thickness is inserted between the

Question

A capacitor has air as dielectric medium and two conducting plates of area $12 cm^{2}$ and they are $0.6 cm$ apart. When a slab of dielectric having area $12 cm^{2}$ and $0.6 cm$ thickness is inserted between the plates, one of the conducting plates has to be moved by $0.2 cm$ to keep the capacitance same as in previous case. The dielectric constant of the slab is : (Given $ϵ_{0} = 8.834 \times 1 0^{- 12} F / m$ )

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Answer:

D

Solution:

$\frac{A ε _{o}}{d} = \frac{A ε _{o}}{( 0.2 + \frac{d}{k} )} 0.6 = 0.2 + \frac{0.6}{k} k = \frac{3}{2}$

TestHub · Accepted Answer

​ d A ε o ​ ​ = ( 0.2 + k d ​ ) A ε o ​ ​ 0.6 = 0.2 + k 0.6 ​ k = 2 3 ​ ​

Physics - Capacitor Question with Solution | TestHub

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