Physics - Capacitor Question with Solution | TestHub

$\begin{array}{rl}& \text{ In steady state, }i=\frac{9}{27\times 10^3}\\ & V_c=I\times R=\frac{9}{27\times 10^3}\times 15\times 10^3=5\mathrm{V}\\ & q=C{V}_c=9\times 10^{-6}\times 5\\ & q=45\times 10^{-6}\mathrm{C}=45\mu \mathrm{C}\end{array}$