Physics - Capacitor Question with Solution | TestHub

The charge on a condenser is given by $Q=CV$.

$\Rightarrow V=\frac{1}{C}Q$

Since the capacitance depends on the construction of the condenser, it is constant. Therefore, the graph will be straight line with slope $=\frac{1}{C}$.
Slope $=\frac{1}{C}=\frac{1}{2\times {10}^{-6}}=5\times {10}^5$