Physics - Capacitor Question with Solution | TestHub

$\mathrm{Q}=\mathrm{C}\mathrm{V}$
The slope of graph will give the equivalent capacitance of the combination.
From graph$\mathrm{A}:$${\mathrm{C}}_1+{\mathrm{C}}_2=\frac{500}{10}=50$…(i)
From graph$\mathrm{B}:$$\frac{{\mathrm{C}}_1{\mathrm{C}}_2}{{\mathrm{C}}_1+{\mathrm{C}}_2}=\frac{80}{10}=8$…(ii)
From equation (i) & (ii)
${\mathrm{C}}_1{\mathrm{C}}_2=400$…(iii)
${\mathrm{C}}_1+\frac{400}{{\mathrm{C}}_1}=50$$\Rightarrow {\mathrm{C}}_1^2-50{\mathrm{C}}_1+400=0$
${\mathrm{C}}_1=\frac{50\pm \sqrt{2500-1600}}{2}=\frac{50\pm 30}{2}$
$=10\mathrm{\mu }\mathrm{F},40\mathrm{\mu }\mathrm{F}$