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PhysicsCapacitorCapacitanceMedium2 minPYQ_2021

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Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacities in the two cases will be:

Question diagram: Two equal capacitors are first connected in series and then

Options:

Answer:

B

Solution:

For series combination,

$\frac{1}{C_{e q_{1}}} = \frac{1}{C} + \frac{1}{C} \Rightarrow C_{e q_{1}} = \frac{C}{2}$

For parallel combination,

$C_{e q_{2}} = C + C \Rightarrow C_{e q_{2}} = 2 C$

$\Rightarrow \frac{C_{e q_{1}}}{C_{e q_{2}}} = \frac{(C / 2)}{2 C} = \frac{1}{4} = 1 : 4$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Capacitance

⏱ 2mℹ️ Source: PYQ_2021

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