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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisMedium2 minPYQ_2022

PhysicsMediumsingle choice

A capacitor $C_{1}$ is charged to a potential difference $V$ . The charging battery is then removed and the capacitor is connected to an uncharged capacitor $C_{2}$ . The potential difference across the combination is

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Solution:

Charge $Q = C_{1} V$ Total capacity of combination (parallel) $C = C_{1} + C_{2}$ $P.D. = \frac{Q}{C} = \frac{C _{1} V}{C _{1} + C _{2}}$

Stream:VITEEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2022

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