Physics - Capacitor Question with Solution | TestHub

Capacitors $C_1$ and $C_2$ are in parallel, their equivalent capacitance is in series with capacitor $C_3$. Hence, the equivalent capacitance of the given circuit is $$C_{eq}=\frac{\left(C_1+C_2\right)C_3}{C_1+C_2+C_3}$$ Charge on capacitor $C_3$ is $$\begin{array}{rl}Q& =V{C}_{\mathrm{eq}}\\ & =\frac{V\left(C_1+C_2\right)C_3}{C_1+C_2+C_3}\end{array}$$ Voltage across $C_3$ is $$=\frac{Q}{C_3}=\frac{V\left(C_1+C_2\right)}{C_1+C_2+C_3}$$