There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are collinear. Then the total number of triangles that can be formed with the vertices at any three of these 12 points is
Options:
Answer:
D
Solution:
$^{12} C_{3} -^{5} C_{3} = 210$

Question

There are 12 points in a plane, no three of which are in the same straight line, except 5 points which are collinear. Then the total number of triangles that can be formed with the vertices at any three of these 12 points is

Options:

Answer:

D

Solution:

$^{12} C_{3} -^{5} C_{3} = 210$

TestHub · Accepted Answer

12 C 3 ​ − 5 C 3 ​ = 210

Mathematics - Permutation & Combination Question with Solution | TestHub

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