Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls

Question

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in queue in such a way that exactly four girls stand consecutively in the queue. Then the value of $\frac{m}{n}$ is

Answer:

5.00

Solution:

$n = |\underline{6} .| \underline{5}$
$m =^{5} C_{4} \times^{6} P_{2} \times 4! \times 5!$
$\frac{m}{n} = 5$

TestHub · Accepted Answer

n = 6 _ . 5 _ m = 5 C 4 × 6 P 2 × 4 ! × 5 ! m n = 5

Mathematics - Permutation & Combination Question with Solution | TestHub

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