Mathematics - Determinant Question with Solution | TestHub

MathematicsDeterminantSystem of equationMedium2 minPYQ_2011

MathematicsMediumsingle choice

The number of values of $k$ for which the linear equations $4 x + k y + 2 z = 0; k x + 4 y + z = 0; 2 x + 2 y + z = 0$ possess a non-zero solution is

Answer:

Solution:

$4 k 2 k 42 211 = 0 \Rightarrow k^{2} - 6 k + 8 = 0 \Rightarrow k = 4, 2$

Stream:JEESubject:MathematicsTopic:DeterminantSubtopic:System of equation

⏱ 2mℹ️ Source: PYQ_2011

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