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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by two curvesEasy2 minPYQ_2024

MathematicsEasysingle choice

The area bounded by the curves $x = 4 - y^{2}$ and the $Y$ -axis is

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Hint: $x = 4 - y^{2} \Rightarrow y^{2} = - x + 4$ $x = 0 \Rightarrow y^{2} = 4 \Rightarrow y = \pm 2$ Area bounded by the curve $x = 4 - y^{2}$ and $y$ -axis is, $= 2 \int_{0}^{2} x d y = 2 \int_{0}^{2} (4 - y^{2}) d y = 2 [4 y - \frac{y ^{3}}{3}]_{0}^{2} = 2 (8 - \frac{8}{3}) = \frac{32}{3}$ sq. unit

Stream:WBJEESubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by two curves

⏱ 2mℹ️ Source: PYQ_2024

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