Let R denote the set of all real numbers. Then the area of the region { ( x , y ) ∈ R × R : x > 0 , y > x 1 , 5 x − 4 y − 1 > 0 , 4 x + 4 y − 17 < 0 } is

Area = 8 13 + 8 20 − lo g e 4 = ( 8 33 − lo g e 4 )

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Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by two curvesHard2 minPYQ_2025

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Let $R$ denote the set of all real numbers. Then the area of the region ${(x, y) \in R \times R : x > 0, y > \frac{1}{x}, 5 x - 4 y - 1 > 0, 4 x + 4 y - 17 < 0}$ is

Question diagram: Let R denote the set of all real numbers. Then the area of t

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Answer:

Solution:

Area $= \frac{13}{8} + \frac{20}{8} - lo g_{e} 4 = (\frac{33}{8} - lo g_{e} 4)$

Stream:JEE_ADVSubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by two curves

⏱ 2mℹ️ Source: PYQ_2025

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