Mathematics - Area Under Curves Question with Solution | TestHub

MathematicsArea Under CurvesArea bounded by two curvesMedium2 minPYQ_2023

MathematicsMediumsingle choice

The area (in sq. units) of the region bounded by curves $y = 3 x + 1, y = 4 x + 1$ and $x = 3$ is

Answer:

Solution:

$Required area = \cdot \int_{0}^{3} [4 x + 1 - (3 x + 1)] d x = \int_{0}^{3} x d x = [\frac{x ^{2}}{2}]_{0}^{3} = \frac{9}{2} sq. units$

Stream:MHT_CETSubject:MathematicsTopic:Area Under CurvesSubtopic:Area bounded by two curves

⏱ 2mℹ️ Source: PYQ_2023

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