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Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeTangents & NormalsHard2 minQB

MathematicsHardnumerical

A tangent to $x y = x^{2} + 1$ at $(α, β)$ is normal to $x^{2} + y^{2} + 2 f y + c = 0$ . Find $1/ (f α)$ .

Answer:

-0.50

Solution:

The tangent slope to the first curve is $(2 α - β) / α$ . The relevant normal slope to the circle is $(β + f) / α$ . Equating as in the normal condition gives $f α = - 2$ using $α β = α^{2} + 1$ . Therefore $1/ (f α) = - 1/2 = - 0.50$ .

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Tangents & Normals

⏱ 2mℹ️ Source: QB

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