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Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeTangents & NormalsMedium2 minQB

MathematicsMediumnumerical

The tangent at $(1, 2)$ to $y_{1} = a x^{2} + b x + 7/2$ is parallel to the normal at $(- 2, 2)$ to $y_{2} = x^{2} + 6 x + 10$ . Find $a - b$ .

Answer:

3.50

Solution:

The point condition gives $a + b = - 3/2$ . The slope of $y_{2}$ at $x = - 2$ is 2, so the normal slope is $- 1/2$ and $2 a + b = - 1/2$ . Hence $a = 1, b = - 5/2$ , and $a - b = 3.50$ .

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Tangents & Normals

⏱ 2mℹ️ Source: QB

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