Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeTangents & NormalsMedium2 minQB

MathematicsMediumsingle choice

The curve $y = f (x) = a x^{3} + b x^{2} + c x + 5$ touches the x-axis at $P (- 2, 0)$ and cuts the y-axis at a point Q where its gradient is 3.

The equation of tangent at Q is

Answer:

Solution:

Q is the y-intercept point $(0, 5)$ and the gradient there is 3. Equation of tangent at Q is $y - 5 = 3 (x - 0)$ , i.e. $3 x - y + 5 = 0$

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Tangents & Normals

⏱ 2mℹ️ Source: QB

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