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Mathematics - Application of Derivative Question with Solution | TestHub

MathematicsApplication of DerivativeMaxima-MinimaHard2 minPYQ_2023
MathematicsHardsingle choice

If the total maximum value of the function fx=3e2sinxsin2x, x0, π2, is ke, then ke8+k8e5+k8 is equal to

Options:

Answer:
A
Solution:

Given function is fx=3e2sinxsin2x

For maxima or minima f'(x)=0

f'x=fx2sinxcosx×ln3e2sinx+sin2x1×2sinx3e×3e2-1sin2x×cosx

fxsin2xln3e2sinx-sinxcosx=0

Now on equation we get, sin2x=0 (not possible)

So, ln3e2sinx=+12

3×e2sinx=e12

sinx=32

fmax=e38=e118ek=e118

ke8+k8e5+k8=e3+e6+e11

Stream:JEESubject:MathematicsTopic:Application of DerivativeSubtopic:Maxima-Minima
2mℹ️ Source: PYQ_2023

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