Mathematics - Application of Derivative Question with Solution | TestHub

$f(x)=\{\begin{array}{cl}1-2x,& x<-1\\ \frac{1}{3}(7-2x),& -1\le x\le 2\\ \frac{1}{3}(7+2x)& 0\le x<2\\ \frac{11}{18}(x-4)(x-5),& x>2\end{array}$
$\therefore$ Local minimum values at $\mathrm{A}\&\mathrm{B}$ $\begin{array}{rl}& \frac{7}{3}-\frac{11}{72}\\ & \Rightarrow \frac{168-11}{72}\Rightarrow \frac{157}{72}\end{array}$